【紅杏】：55線下股價(jià)上穿13線?
MA13:=MA(C,13);?
EMA13:=EMA(C,13);?
EMA34:=EMA(C,34);?
EMA55:=EMA(C,55);?
A1:=EMA55>EMA34 AND EMA34>EMA13;?
A2:=MA13>O;?
A3:=CROSS(C,MA13);?
紅杏:=A1 AND A2 AND A3;

注：在“紅杏”這個(gè)信號(hào)的公式里，我沒有設(shè)置13要走平或者起翹，并且設(shè)定空頭排列的時(shí)候應(yīng)用了“EMA（指數(shù)平滑移動(dòng)平均線）”，而不是“MA（簡(jiǎn)單平均線），這樣就不會(huì)漏掉新股（這里指日線圖中還沒有出現(xiàn)34或55的股票）。如果要求13線走平或起翹情況下的“紅杏”，則公式如下：?
MA13:=MA(C,13);?
EMA13:=EMA(C,13);?
EMA34:=EMA(C,34);?
EMA55:=EMA(C,55);?
A1:=EMA55>EMA34 AND EMA34>EMA13;?
A2:=MA13>O;?
A3:=EMA13>=REF(EMA13,2);?
A4:=CROSS(C,MA13);?
紅杏:=A1 AND A2 AND A3 AND A4;

【一陽穿】：一陽上穿135線?
MA13:=MA(C,13);?
MA34:=MA(C,34);?
MA55:=MA(C,55);?
A1:=O
A2:=C>MA13 AND C>MA34 AND C>MA55;?
A3:=(C-REF(CLOSE,1))/REF(CLOSE,1)*100 > 5;?
一陽穿:=A1 AND A2 AND A3;

【黑客紅衣】：13線上穿55?
MA13:=MA(C,13);?
MA34:=MA(C,34);?
MA55:=MA(C,55);?
A1:=MA34MA13 AND C>MA55;?
A2:=CROSS(MA13,MA55);?
A3:=(O-MA55)/MA55*100<6 OR (C-MA13)/MA13*100<6;?
黑客紅衣:=A1 AND A2 AND A3;

【多頭列】：135線形成多頭排列?
MA13:=MA(C,13);?
MA34:=MA(C,34);?
MA55:=MA(C,55);?
A1:=MA13>MA34 AND MA34>=MA55;?
A2:=CROSS(MA34,MA55);?
A3:=(MA13-MA55)/MA55*100 < 8;?
A4:=(O-MA13)/MA13*100 < 6;?
A5:=(C-MA13)/MA13*100 < 12;?
A6:=C>MA55;?
多頭列:=A1 AND A2 AND A3 AND A4 AND A5 AND A6;

【梅開二度】：55線上13上穿34?
MA13:=MA(C,13);?
MA34:=MA(C,34);?
MA55:=MA(C,55);?
A1:=MA13>MA55 AND MA34>MA55;?
A2:=CROSS(MA13,MA34);
A3:=C>MA13 AND C>MA34;?
梅開二度:=A1 AND A2 AND A3;

【揭竿起】：股價(jià)從135線上揭竿而起?
MA13:=MA(C,13);?
MA34:=MA(C,34);?
MA55:=MA(C,55);?
A1:=MA13>MA55;?
A2:=C>MA13;?
A3:=(O<=REF(C,1) AND (C-REF(C,1))/REF(C,1)*100>6) OR (O>REF(C,1) AND (C-O)/O*100>6);?
A4:=(C-MA13)/MA13*100 < 12;?
A5:=(O-MA13)/MA13*100 < 3;?
A6:=(O-MA13)/MA13*100 > -3;?
A7:=(O-MA55)/MA55*100 < 12;?
A8:=(MA13-MA55)/MA55*100 < 12;?
AA:=A1 AND A2 AND A3 AND A4 AND A5 AND A6 AND A7 AND A8;?
B1:=MA13
B2:=O>MA13 AND O>MA34 AND C>MA55;?
B3:=(O<=REF(C,1) AND (C-REF(C,1))/REF(C,1)*100>6) OR (O>REF(C,1) AND (C-O)/O*100>6);?
B4:=(O-MA55)/MA55*100 < 3;?
B5:=(O-MA55)/MA55*100 > -3;?
BB:=B1 AND B2 AND B3 AND B4 AND B5;?
揭竿起:=AA OR BB;

注：揭竿起這個(gè)信號(hào)比較抽象，編寫稍有難度，考慮到多、空頭的不同情況，只能讓該公式盡量涉及又不至于遺漏，精確度較差，但在實(shí)盤監(jiān)控的時(shí)候已經(jīng)可以確保我們能夠及時(shí)發(fā)現(xiàn)可能形成揭竿起的股票了。

【螞蟻】：連續(xù)5小陽?
MA13:=MA(C,13);?
MA34:=MA(C,34);?
MA55:=MA(C,55);?
A1:=MA13>MA55;?
A2:=(C-MA13)/MA13*100 < 8;?
A3:=O>REF(O,1) AND REF(O,1)>REF(O,2) AND REF(O,2)>REF(O,3) AND REF(O,3)>REF(O,4);?
A4:=C>REF(C,1) AND REF(C,1)>REF(C,2) AND REF(C,2)>REF(C,3) AND REF(C,3)>REF(C,4);?
A5:=C>=O AND REF(C,1)>=REF(O,1) AND REF(C,2)>=REF(O,2) AND REF(C,3)>=REF(O,3) AND REF(C,4)>=REF(O,4);?
A6:=COUNT(BETWEEN((C-REF(C,1))/REF(C,1)*100,0,5) ,5)=5;?
AA:=A1 AND A2 AND A3 AND A4 AND A5 AND A6;?
B1:=MA13MA55;?
B2:=(C-MA55)/MA55*100 < 8;?
B3:=O>REF(O,1) AND REF(O,1)>REF(O,2) AND REF(O,2)>REF(O,3) AND REF(O,3)>REF(O,4);?
B4:=C>REF(C,1) AND REF(C,1)>REF(C,2) AND REF(C,2)>REF(C,3) AND REF(C,3)>REF(C,4);?
B5:=C>=O AND REF(C,1)>=REF(O,1) AND REF(C,2)>=REF(O,2) AND REF(C,3)>=REF(O,3) AND REF(C,4)>=REF(O,4);?
B6:=COUNT(BETWEEN((C-REF(C,1))/REF(C,1)*100,0,5) ,5)=5;?
AB:=B1 AND B2 AND B3 AND B4 AND B5 AND B6;?
螞蟻:=AA OR BB;?

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?來源:程序化99

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?來源: www.weiqiv.net.cn

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